Change of Coordinates Visualizer
A fixed point in ℝ² gets new coordinates when you change basis — only the grid moves, not the point.
A basis of \(\mathbb{R}^n\) is a set of \(n\) linearly independent vectors. Given two ordered bases
\( \mathcal{V} = \{v_1, \ldots, v_n\}, \quad \mathcal{U} = \{u_1, \ldots, u_n\}, \)
stack the basis vectors as columns of \(\mathbf{V} = [\,v_1\ \cdots\ v_n\,]\) and \(\mathbf{U} = [\,u_1\ \cdots\ u_n\,]\), each expressed in standard coordinates.
Change of coordinates matrix:
\[ \mathbf{S} = \mathbf{U}^{-1}\,\mathbf{V}. \]
If \([\mathbf{x}]_{\mathcal{V}}\) is the coordinate vector of \(\mathbf{x}\) in basis \(\mathcal{V}\), its coordinate vector in basis \(\mathcal{U}\) is
\[ [\mathbf{x}]_{\mathcal{U}} = \mathbf{S}\,[\mathbf{x}]_{\mathcal{V}}. \]
Key ideas:
- \(\mathbf{S}\) takes coordinates in \(\mathcal{V}\) to coordinates in \(\mathcal{U}\); the same geometric point \(\mathbf{x}\) is described by two different lists of numbers.
- The inverse \(\mathbf{S}^{-1} = \mathbf{V}^{-1}\mathbf{U}\) goes the other way, from \(\mathcal{U}\) back to \(\mathcal{V}\).
- If \(\mathcal{U}\) is the standard basis, then \(\mathbf{U} = \mathbf{I}\) and \(\mathbf{S} = \mathbf{V}\): the columns of \(\mathbf{V}\) themselves convert \(\mathcal{V}\)-coordinates to standard ones.
- \(\mathbf{S}\) exists only when \(\mathbf{U}\) is invertible — equivalently, when \(\{u_1, \ldots, u_n\}\) really is a basis.
For a step-by-step numerical computation of \(\mathbf{S} = \mathbf{U}^{-1}\mathbf{V}\) with fractions and surds, use the Change of Coordinates Matrix Calculator.
Bases (V: Initial, U: Final)
V (initial)
U (final)