Fundamental Theorem of Calculus, Part 2

The Evaluation Theorem. Fix the limits \(a\) and \(b\) of \(\int_a^b f(t)\,dt\), then sweep the intermediate upper limit \(x\) from \(a\) toward \(b\): the running area \(\int_a^x f(t)\,dt\) equals \(F(x)-F(a)\), reaching the answer \(F(b)-F(a)\) at \(x=b\).

\[\int_a^b f(t)\,dt \;=\; F(b)-F(a),\qquad F'(x)=f(x)\]
Integrand \(f\)
e.g. x^2-2, x*sin(x), exp(-x^2), 1/(1+x^2)
-10.00
\(\int_a^x f(t)\,dt\)
0.00000
\(F(x)-F(a)\)
0.00000
\(x\) (intermediate)
-10.000
\(b\) (upper limit)
10.000
\(\displaystyle\int_a^x f(t)\,dt\) — signed area
\(F(x)\) with \(F'(x)=f(x)\) — the difference \(F(x)-F(a)\)
\(\displaystyle\int_a^x f(t)\,dt\) — traced area under graph of \(f(t)\)
\(F(x)-F(a)\) — right side (compare, exactly)
Cite this tool
Kapita, S. (2026). Fundamental Theorem of Calculus, Part 2. Math Tools. https://shelvean.github.io/math-tools/ftc2.html